Question

what is the area of quadrilateral ABCD​

Answer 1

Answer:

Area of quadrilateral

ABCD = Area of triangle

ABC= (1)+(2)=24+60=84 squre cm.

Answer 2

Step-by-step explanation:

In rt.∆ ADB , BY PYTH. THEORM

BD² = [4]²+[3]² = 16 + 9 = 25

BD = √25 = 5cm

Now , ar of ∆ADB = 1/2 × BASE × HEIGHT

=

$\frac{1}{2} \times 5 \times 4$

$\frac{1}{2 } \times 20$

$10 {cm}^{2}$

NOW FIND AR OF ANOTHER ∆ BY HERON'S FORMULA AND ADD THE AREAS OF BOTH ∆s AND THAT WILL GIVE U THE AR OF QUAD.

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