What is the area of quadrilateral given? Please don't spam and give the answer in steps or else, I'll not take long to report you.
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hey friend there is your answer
Step-by-step explanation:
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Answer:
it's 104 cm²
Step-by-step explanation:
in triangle DBC
DB²+BC²=DC²
DB²+64=289
DB²=225
DB=15
In triangle DAB
DB²=AD²+AB²
225=81+AB²
144 = AB²
AB=12
Ar(ADB)=1/2*12*9=54
Ar(DBC)=1/2*8*15=60
Ar(ADCB)=54+60=104cm²
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