What is the area of rectangle ABCD, if points A, B, C, and D have the following coordinates? Hint: draw the rectangle on a coordinate plane.
c
* A(2, 5), B(2 2 3 , 5), C(2 2 3 , 5 3 5 ), D(2, 5 3 5 )
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Area of rectangle ABCD = 2/5 Sq units
Step-by-step explanation:
A = ( 2 , 5)
B = (2 2/3 , 5) = (8/3 , 5)
C = (2 2/3 , 5 3/5) = (8/3 , 28/5)
D = (2 , 5 3/5) = ( 2 , 28/5)
Its a Rectange
AB = CD = 8/3 - 2 = 2/3
BC = AD = 28/5 - 5 = 3/5
Area of rectangle = (2/3)(3/5)
= 2/5 Sq units
Area of rectangle ABCD = 2/5 Sq units
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