Question

What is the area of rhombus ABCD if AC = 10 cm BD = 6 cm​

Answer 1

Answer is 30cm2

Step-by-step explanation:

1/2×10×6

=30

Answer 2

The area of the rhombus is 30 cm².

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Let's understand a few concepts:

What is a rhombus?

A rhombus is a parallelogram that has all its sides equal in length.

How to find the area of a rhombus?

The area of a rhombus can be calculated in terms of its diagonal by the following formula:

$\boxed{\bold{Area \: of\:a\:rhombus = \frac{1}{2} \times [product\:of\:diagonals] \:sq. \:units=\frac{1}{2} \times d_1\times d_2\:sq. \:units}}$

where d₁ = diagonal 1 and d₂ = diagonal 2

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Let's solve the given problem:

ABCD is a rhombus

The length of one diagonal, AC = 10 cm

The length of other diagonal, BD = 6 cm

Therefore,

The area of the rhombus ABCD is,

= $\frac{1}{2} \times product\: of\: two \:diagonals\:$

= $\frac{1}{2} \times AC \times BD$

= $\frac{1}{2} \times 10 \times 6$

= $5 \times 6$

= $\bold{30\:cm^2}$

Thus, the area of a rhombus ABCD is 30 cm².

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