Question

what is the area of square of length 6x-3?​

Answer 1

As per the given data in the question

In the above question it is given that

we have find the value of given expression

Given square of length $6X-3$

Find the value of area of square?

We know that area of square $A=s^{2}$

We get ,$6X-3$

putting value of formula

$Area =(6X-3) (6X-3)\\=(36X^{2} -18X)-(18X-9)\\=36X^{2} -18X-18X+9\\=36X^{2} -36X+9$

Hence the required solution will be $36X^{2} -36X+9$.

Answer 2

Here measure of side of a square is given to be 6x -3

We have to find the area of the square

Area of square = side × side

Putting the value of side in the above formula

Area=(6x-3)(6x-3)

=(36x²-18x)-(18x-9)

=36x²-18x-18x+9

=36x²-36x+9

Hence, the area of the square will be 36x²-36x+9 square units.