What is the area of the cardboard needed to make the
given net if cube is opened and perimeter is 48 cm and one side is 4 cm
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Answered by
2
Answer:80 sq. cm
Step-by-step explanation:
T.S.A of Cube = 6×s^2
= 6 × 4 × 4
= 80 sq. cm.
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Step-by-step explanation:
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