Question

What is the area of the composite figure?
262 cm2
264 cm2
266 cm2
268 cm2

Answer 1

Answer:

264 $cm^{2}$ is the required area of the given figure .

Step-by-step explanation:

Explanation:

Here , we divide the figure in three part

First part is ABCD which is a square ,

second part is XYZO which is a trapezium and

third part is  PQRS which is a rectangle

Step1:

Area of first part which is a square(ABCD) = a ×a

                                                             = 10 ×10 = 100$cm^{2}$

(where side of given square is 10cm)

Step2:

Area of trapezium (XYZO) = $(\frac{a+b}{2}) h$

 put the value of a, b and h .

where 'a' = OZ = OA +AZ = 3+5=8cm

base (b) = XY = 14cm and height (h) = 4cm.

Therefore ,

Area of trapezium (XYZO) = $\frac{(14+8)}{2}4$

                                         = 22×2 = 44$cm^{2}$

Step3:

Area of rectangle PQRS = $lb$

                                     =  20 × 6 = 120$cm^{2}$

(Where length = 20 cm and breadth = 6cm)

Step4:

Therefore , area of the given figure = (ABCD)+(XYZA)+(PQRS)

                                                           = (100+44+120)$cm^{2}$

                                                          = 264 $cm^{2}$

Final answer :

Hence , the area of the composite figure is 264$cm^{2}$ .

Answer 2

Answer:

B) 264 cm2

Step-by-step explanation:

just did it on edge