Question

What is the area of the figure?

32 m 2
can't be determined
20 m 2
24 m 2

Answer 1

Answer:

20 m^2

Step-by-step explanation:

This figure is divided into 1 triangle and 1 rectangles

Area of rectangle = l * b

Area of triangle =  $\frac{1}{2}*b*h$

1 st Area of triangle = 1/2 * 4 * 2

                                  = 4 sq. uts

Down the rectangle = l * b

                                  = 8 * 2 = 16 sq.uts

So ,Total area of triangle = 16 + 4 = 20 sq. uts

                                           = 20 m^2

Answer 2

Step-by-step explanation:

Given -

Figure

To Find :-

Area of the figure

As we know that :-

• Area of rectangle = length × breadth
• Area of triangle = 1/2×base×height

In the given figure we see that ABCD is a rectangle

Now,

Area of rectangle ABCD is l × b

» 8 × 2

• » 16 m²

And

Area of triangle EDF is 1/2×base×height

» 1/2 × 4 × 2

• » 4 m²
• Area of the figure = Area of rectangle ABCD + Area of triangle EDF

» 16 + 4

» 20 m²

Hence,

The Area of the figure is 20 m²

Note :-

ΔEDF is a right-angle triangle.

Formula Used :-

• Area of rectangle = l × b
• Area of triangle = 1/2×base×height