what is the area of the largest circle that can be drawn inside a square of side 28 cm ?
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88 cm^ is. the area of circle
Sumitstylish2004:
sorry friend it is wrong
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4/x - 3 = 5/(2x + 3)
(4 - 3x)/x = 5/(2x + 3)
(4 - 3x)(2x + 3) = 5x
8x + 12 - 6x^2 - 9x = 5x
12 - x - 6x^2 = 5x
12 - x - 6x^2 - 5x = 0
12 -6x - 6x^2 = 0
6x^2 + 6x - 12 = 0
(6x + 12)(x - 1) = 0
6x + 12 = 0 , x - 1 =0
x = -2 , x = 1.
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Betty BellaItalia, Professor of Math at KSC SARAJEVO (1977-present)
Answered May 29
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Vaibhav Keshari, 10 Physics & Mathematics, Sant Atulanand Convent School, Main Branch
Answered Jul 4
4/x-3=5/2x+3
=4(2x+3)=5(x-3)
=8x+12=5x_15
=8x-5x=-15-12
=3x=-27
=x=-27/3
=x=-9
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Susai Raj, former Retired Teacher.
Answered Mar 19
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(4/x) - 3 = 5/(2x+3)
Implies (4–3x)/x = 5/(2x+3).
By cross multiplying we get
5x = (4–3x)(2x+3). ie.
5x = -6x^2 - x + 12. ie.
6x^2 + 6x - 12 = 0. ie.
x^2 + x - 2 = 0. ie
(x+2)(x-1) = 0. ie.
x = -2 or x = 1.
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(4 - 3x)/x = 5/(2x + 3)
(4 - 3x)(2x + 3) = 5x
8x + 12 - 6x^2 - 9x = 5x
12 - x - 6x^2 = 5x
12 - x - 6x^2 - 5x = 0
12 -6x - 6x^2 = 0
6x^2 + 6x - 12 = 0
(6x + 12)(x - 1) = 0
6x + 12 = 0 , x - 1 =0
x = -2 , x = 1.
16.2k Views · View Upvoters
Upvote· 34
Share
Comment...
Betty BellaItalia, Professor of Math at KSC SARAJEVO (1977-present)
Answered May 29
Continue Reading
271 Views
Upvote
Share
Comment...
Sponsored by Digit General Insurance
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Vaibhav Keshari, 10 Physics & Mathematics, Sant Atulanand Convent School, Main Branch
Answered Jul 4
4/x-3=5/2x+3
=4(2x+3)=5(x-3)
=8x+12=5x_15
=8x-5x=-15-12
=3x=-27
=x=-27/3
=x=-9
266 Views
Upvote
Share
Comment...
Susai Raj, former Retired Teacher.
Answered Mar 19
Continue Reading
(4/x) - 3 = 5/(2x+3)
Implies (4–3x)/x = 5/(2x+3).
By cross multiplying we get
5x = (4–3x)(2x+3). ie.
5x = -6x^2 - x + 12. ie.
6x^2 + 6x - 12 = 0. ie.
x^2 + x - 2 = 0. ie
(x+2)(x-1) = 0. ie.
x = -2 or x = 1.
611 Views
Upvote
Share
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