what is the area of the largest triangle that is inscribed in a semicircle of radius r unit...........
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The largest triangle in a semicircle has his base equal to the diameter of the semicircle
⇒base of Δ =diameter of semicircle
= 2r units
∴Base of Δ = 2r
The triangles height must be the radius of the semicircle
⇒ height of the Δ = radius of the semicircle
= r units
Now we have
base = 2r
height = r
area of Δ = (1/2) b×h
= (1/2) 2r × r units²
= 2r²/2
= r²
∴Area of the largest triangle that can be inscribed in the given semicircle is r² units²
⇒base of Δ =diameter of semicircle
= 2r units
∴Base of Δ = 2r
The triangles height must be the radius of the semicircle
⇒ height of the Δ = radius of the semicircle
= r units
Now we have
base = 2r
height = r
area of Δ = (1/2) b×h
= (1/2) 2r × r units²
= 2r²/2
= r²
∴Area of the largest triangle that can be inscribed in the given semicircle is r² units²
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