Question

What is the area of the plates of a 2f parallel plate capacitor, given separation between the plates is 0.5cm?

Answer 1

Answer:

1130

Explanation:

Capacitance for a parallel plate capacitor = C =2F

Seperation between parallel capacitor = 0.5cm = 5×10⁻³m

C = (ε₀ A)/d

A = (C×d)/ε₀

A = 4πCd/(4πε₀)

A = 4πCdk   (where k = 1/4πε₀)

A = 4×π×2×(0.5×10⁻²)×(9×10⁹)

A = 36π×10⁷ m²

A = 113.097 × 10⁷ m²

A = 1.13×10⁹ m²

Thus, 1.13×10³km²

= 1130 km²

Since,the area of the plates is too large, thus to avoid the situation, the capacitance will be taken in the range of µF.