Question

what is the area of the plates of a parallel plate capacitor of capacitance 2F and with separation between plates 0.5 cm?

Answer 1

For a parallel plate capacitor,

C = (ε₀ A)/d

∴ A = (C×d)/ε₀
∴ A = 4πCd/(4πε₀)
∴ A = 4πCdk   (where k = 1/4πε₀)
∴ A = 4×π×2×(0.5×10⁻²)×(9×10⁹)
∴ A = 36π×10⁷ m²
∴ A = 113.097 × 10⁷ m²
∴ A ≈ 1.13×10⁹ m²

Answer 2

Answer:

11.3×10^7 square metres

Explanation: