Question

What is the area of the quadrilateral ABCD shown in the figure below? (all measurements are in cm) Take √6 = 2.45

Answer 1

Answer:

Join BD , 2 denotes square

Step-by-step explanation:

Then In triangle ADB,

BD2=AB2+AD2

BD=√16+9= √25=5

ar(ADB)=1/2×4×3

=6

Then In ,

triangle CDB

apply herons formula

And

add the ar(ADB)+ar(CBD)

Answer 2

Answer:

Area of quadrilateral ABCD = area of triangle ABD + area of triangle BDC

》 6 + 14.7 cm^2

》 20.7 cm^2.

therefore, area of quadrilateral ABCD = 20.7 cm^2

hope it helps.........