Math, asked by ritugiri26, 5 hours ago

What is the area of the rectangle whose dimensions are (a + 3) and (3 - a) ?
(a²-6)
9-a²
a²-6
6-a²

Answers

Answered by goldipal170
0

Answer:

9-a^2

Step-by-step explanation:

length=(a+3)

breadth=(3-a)

Area of rectangle =length×breadth

=(a+3)×(3-a)

=3a-a^2+9-3a

=9-a^2

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