What is the area of the rectangle whose dimensions are (a + 3) and (3 - a) ?
(a²-6)
9-a²
a²-6
6-a²
Answers
Answered by
0
Answer:
9-a^2
Step-by-step explanation:
length=(a+3)
breadth=(3-a)
Area of rectangle =length×breadth
=(a+3)×(3-a)
=3a-a^2+9-3a
=9-a^2
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