what is the area of the rectangle whose length is (2x-3) the width is (x+)?
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GiveN :-
- Length of rectangle = 2x - 3
- Breadth of rectangle = x + 1
To FinD :-
- Area of the rectangle
SolutioN :-
★ Area of the rectangle = L × B
→ Area = ( 2x - 3 ) ( x + 1 )
→ Area = 2x² + 2x - 3x - 3
→ Area = 2x² - x - 3
∴ Area of rectangle = 2x² - x - 3
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