Math, asked by freyaaa707, 1 month ago

what is the area of the rectangle whose length is (2x-3) the width is (x+)?​

Answers

Answered by Anonymous
22

GiveN :-

  • Length of rectangle = 2x - 3
  • Breadth of rectangle = x + 1

To FinD :-

  • Area of the rectangle

SolutioN :-

Area of the rectangle = L × B

→ Area = ( 2x - 3 ) ( x + 1 )

→ Area = 2x² + 2x - 3x - 3

→ Area = 2x² - x - 3

Area of rectangle = 2x² - x - 3

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