Question

what is the area of the rectangle whose length is (x+5) and width (x-5)?​

Answer 1

Answer:

The both ways I have done are correct! you can do any one of them!

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Answer 2

The area of the rectangle whose length is (x + 5) and width (x - 5) is x² - 25

Given :

For a rectangle length is (x + 5) and width is (x - 5)

To find :

The area of the rectangle

Solution :

Step 1 of 2 :

Write down Length and width of the rectangle

Here it is given that for a rectangle length is (x + 5) and width is (x - 5)

Length of the rectangle = (x + 5)

Width of the rectangle = (x - 5)

Step 2 of 2 :

Find area of the rectangle

The area of the rectangle

= Length of the rectangle × Width of the rectangle

$\displaystyle \sf{ = (x + 5) \times (x - 5) }$

$\displaystyle \sf{ = {(x)}^{2} - {(5)}^{2} \: \: \: \bigg[ \: \because \:(a + b)(a - b) = {a}^{2} - {b}^{2} \bigg] }$

$\displaystyle \sf{ = {x}^{2} - 25 }$

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