Question

what is the area of the rhombus ABCD below if AC is equals to 6 cm and BC is equals to 4 cm​

Answer 1

Answer:

15.9 cm²

Step-by-step explanation:

in ΔABC and ΔADC

         AB   =   AD     (sides of a rhombus are equal)

         AC   =   AC     (common)

         BC   =    DC    (sides of a rhombus are equal)

 ∴  ΔABC ≅ ΔADC  (SSS congruency)

ar(ΔABC) = 1/2(bh)

                = 1/2(6x√7)

                = 3√7

∴ar(ΔADC) = 3√7

∴ar(ABCD) = ar(ΔABC) + ar(ΔADC)

                  = 3√7 + 3√7

                  = 6√7

                  = 6x2.65

                  = 15.9 cm²