Question

what is the area of the sector of a circle of radius is 5 cm if angle of sector is 60 degree​

Answer 1

Answer:

radius r=5cm

angle of sector =60degree

area of sector=angle/360 ×πr^2=(60/360)×(22/7)×5×5

=13.09sqcm. approximately

Answer 2

Given :-

• Radius of circle r = 5cm
• Angle of sector ¢ = 60°

We know that :-

• Area of a sector of a circle = ¢/360° × πr²

By putting all the values :-

→ ¢/360° × πr²

→ 60°/360° × 22/7 × 5²

→ 1/6 × 22/7 × 25

→ 13.09cm²

The area of the sector of a circle is 13.09cm².