what is the area of the sector whose diameter is 40 mm and angle is 120°
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Step-by-step explanation:
Diameter = 40 mm
Therefore, Radius = 40/2 = 20 mm
Angle Subtended = 120° = 120×π/180©
= 2π/3 radians
So, Area of Sector = 1/2.r².∅
= 1/2.(20)².2π/3 = 400/2.2π/3 = 400π/3 mm²
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