What is the area of the shaded portion if the area of the circle is 56 cm2?
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Answers
Answer:
Here's your answer
Step-by-step explanation:
Given => For circle
Area(a) = 56cm²
a = πr²
56 = 22/7*r²
r² = 56*7/22
r = √17.81
r = 4.2
Diagnoal (d) = 2*4.2 = 8.4
So , 4 chords joining forms a square
side of square = d /root2
a=8.4/1.414 (root2 = 1.414)
a = 5.9
a/2 = 5.9/2 = 2.95
area of two shaded traingles = 1/2*b*h
1/2*2.95*2.95
= 4.35
area of segment = Q/360*pier^2
90/360*22/7*4.2*4.2
0.25*3.14*17.65
13.84
So , the finl answer is
area of shaded region = 13.84+4.35
18.19cm^2
hope you understand
Answer:
18.19cm sq.
Step-by-step explanation:
Given = For circle:
Area(a) = 56cm sq.
=>a = πr²
=>56 = 22/7*r²
=>r² = 56*7/22
=>r = √17.81
=>r = 4.2cm sq.
Diagnoal (d) = 2*4.2 = 8.4cm sq.
Side of square = d /root2
=>a=8.4/1.414 (root2 = 1.414)
=>a = 5.9
=>a/2 = 5.9/2 = 2.95cm sq.
Area of two shaded triangles = 1/2*b*h
=1/2*2.95*2.95
= 4.35cm sq.
Area of segment = Q/360*pier^2
=90/360*22/7*4.2*4.2
=0.25*3.14*17.65
=13.84 cm sq.
The answer of the area that is in the shaded region = 13.84+4.35
=18.19cm sq.