What is the area of the square if the length of its diagonal is 3.6 cm
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Answered by
1
let side of square =x
by Pythagoras theorem
x^2 +x^2={3.6}^2
2x^2=12.96
x^2=6.48
area =x^2 =6.48 cm^2
by Pythagoras theorem
x^2 +x^2={3.6}^2
2x^2=12.96
x^2=6.48
area =x^2 =6.48 cm^2
Answered by
0
area of the square when diagonal is given=root2×a
=root2 ×3.6
=3.6under root2
=root2 ×3.6
=3.6under root2
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