Question

what is the area of the trapezium ABCD,if the long base is AB=16cm, the short base CD=6cm and the height is 3cm?​

Answer 1

Answer:

Step-by-step explanation:

Answer:

Area of trapezium =1/2( sum of the parallel side)×height

=1/2(16+6)×3

=1/2(22)×3

=33cm^2

HOPE THAT IT WILL HELP YOU...

Answer 2

$\large\underline{\sf{Given- }}$

A trapezium ABCD with

Longest side AB as base = 16 cm

Shortest parallel side, CD = 6 cm

Distance between AB and CD, h = 3 cm

$\large\underline{\sf{To\:Find - }}$

Area of trapezium ABCD

$\begin{gathered}\Large{\bold{{\underline{Formula \: Used - }}}}  \end{gathered}$

$\red{\boxed{ \rm{ \: Area_{trapezium} = \frac{1}{2}(Sum \: of \: \parallel \: sides) \times height}}}$

$\large\underline{\sf{Solution-}}$

Given that,

Length of longest base, AB = 16 cm

Length of parallel side, CD = 6 cm

Distance between parallel sides, h = 3 cm

So,

$\rm :\longmapsto\:{ \: Area_{trapezium} = \dfrac{1}{2}(Sum \: of \: \parallel \: sides) \times height}$

$\rm \: = \: \:\dfrac{1}{2} \times (16 + 6) \times 3$

$\rm \: = \: \:\dfrac{1}{2} \times (22) \times 3$

$\rm \: = \: \:11 \times 3$

$\rm \: = \: \:33 \: {cm}^{2}$

$\bf\implies \:Area_{trapezium} \: = \: 33 \: {cm}^{2}$

Additional Information :-

Let's solve one other problem!!

Question :- The parallel sides of a trapezium are in the ratio 4 : 3 and distance between parallel sides is 3 cm. If the area of trapezium is 84 sq. cm. Find the parallel sides of trapezium.

Solution :- Let assume that ABCD be a trapezium with AB || CD.

Since, parallel sides are in the ratio 4 : 3.

Let assume that

Length of AB = 4x cm

Length of CD = 3x cm

Distance between parallel sides, h = 3 cm

Area of trapezium ABCD = 84 sq. cm.

So, using formula, we have

$\rm :\longmapsto\:{ \: Area_{trapezium} = \dfrac{1}{2}(Sum \: of \: \parallel \: sides) \times height}$

$\rm :\longmapsto\:84 = \dfrac{1}{2} \times (4x + 3x) \times 3$

$\rm :\longmapsto\:84 = \dfrac{1}{2} \times 7x \times 3$

$\rm :\longmapsto\:x = \dfrac{84 \times 2}{3 \times 7}$

$\bf\implies \:x = 8$

Hence,

Length of AB = 4x = 4 × 8 = 32 cm

Length of CD = 3 × 8 = 24 cm