Question

what is the area of the trapezium DBCE if the area of ABC is 18cm​

Answer 1

Answer:

Step-by-step explanation:

By ratios of area of similar triangle.

arABC/ arADE= (AB/AD)^2

18/arADE=( 3/1)^2. (Given)

18/arADE= 9/1

arADE= 1/9×18 ( ON RECIPROCAL)

arADE= 2cm^2

arABC-arADE= arDBCE

18-2= arDBCE

16cm^2= arDBCE

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