Question

what is the area of the triangle 16 20 12

Answer 1

Since the sides are given, we use Heron's Formula:

$\sqrt{s(s-a)(s-b)(s-c)}$

a = 16

b = 20

c = 12

s = semi-perimeter = 12+16+20/2 = 48/2 = 24

$\sqrt{24(24-16)(24-20)(24-12)}\\ = \sqrt{24* 8 * 4 * 12}\\ = \sqrt{9216}\\ = 96$