Question

What is the area of the triangle ADE in the following figure?

(Maths NCERT Exemplar, Example Sums)
I want to know how this sum is done.

Answer 1

Answer:

Area of rectangle= 10 × 8 cm^2 = 80 cm^2

∆ ADE and rectangle ABCD lie on same base AD and between same parallels AD and BC.

Therefore, area of ∆ ADE= 1/2× 80 cm^2 = 40 cm^2

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Answer 2

Answer:

the base is 8cm and height is 10 cm

1/2×8×10=40cm²