Question

What is the area of the triangle formed by joining the points (8, 0), (12, 0), and (12, 4)? show in Cartesian plane​

Answer 1

Answer: The area of a triangle is 32 sq units.

Explanation-Given the points are (8,0),(12,0), and (12,4).

Find the area of a triangle

Solution - Given points are (8,0),(12,0),(12,4).

                                              $x_1y_1$, $x_2y_2$, $x_3y_3$

We know,

Area of triangle=$\frac{1}{2}|x_1(y_2-y_3)|+x_2(y_3-y_2)+x_3(y_1-y_2)$

$=\frac{1}{2}|8(0-4+12)+12(4-0)+12(0-0)|$

$=\frac{1}{2}|8\times -4+12\times 4+0|$

$=\frac{1}{2}|-32+48|$

$=\frac{1}{2}\times 168$

$A=32sq units$

Hence, the area of a triangle is 32sq units.

#SPJ2

Answer 2

Answer:

The area of a triangle is 32 sq units.

Step-by-step explanation:

Given the points are (8,0),(12,0), and (12,4).

Find the area of a triangle

Solution - Given points are (8,0),(12,0),(12,4).

�

1

�

1

x

1

y

1

,

�

2

�

2

x

2

y

2

,

�

3

�

3

x

3

y

3

We know,

Area of triangle=

1

2

∣

�

1

(

�

2

−

�

3

)

∣

+

�

2

(

�

3

−

�

2

)

+

�

3

(

�

1

−

�

2

)

2

1

∣x

1

(y

2

−y

3

)∣+x

2

(y

3

−y

2

)+x

3

(y

1

−y

2

)

=

1

2

∣

8

(

0

−

4

+

12

)

+

12

(

4

−

0

)

+

12

(

0

−

0

)

∣

=

2

1

∣8(0−4+12)+12(4−0)+12(0−0)∣

=

1

2

∣

8

×

−

4

+

12

×

4

+

0

∣

=

2

1

∣8×−4+12×4+0∣

=

1

2

∣

−

32

+

48

∣

=

2

1

∣−32+48∣

=

1

2

×

168

=

2

1

×168

=

32

A=32squnits

Hence, the area of a triangle is 32sq units.