What is the area of the triangle formed from (0,-1) , (0,4) , and (4,-1)?
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Answered by
2
Hey buddy here is ur answer !!
SOLUTION :
A (0,-1)
B (0,4)
C (4,-1)
So by distance formula ;
root (x2-x1)^2 + (y2-y1)^2
For AB
root {(4-0)^2} +{ (-1) - (-1)}^2
root 16 + 0
root 16
For BC
root { 4-0}^2 + {-1-4 }^2
root 16 + 25
root 41
For AC
root {4-0}^2 + {-1-(-1)}^2
root 16 + 0
root 16
Hence AB = AC not equal to BC
Hope u get the concept !!!
SOLUTION :
A (0,-1)
B (0,4)
C (4,-1)
So by distance formula ;
root (x2-x1)^2 + (y2-y1)^2
For AB
root {(4-0)^2} +{ (-1) - (-1)}^2
root 16 + 0
root 16
For BC
root { 4-0}^2 + {-1-4 }^2
root 16 + 25
root 41
For AC
root {4-0}^2 + {-1-(-1)}^2
root 16 + 0
root 16
Hence AB = AC not equal to BC
Hope u get the concept !!!
Answered by
1
Answer:
hope this answer useful to you mate
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