Question

what is the area of the triangle having sides of length 10 cm , 8 cm and 6 cm ?
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Answer 1

Answer:

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Step-by-step explanation:

area of triangle :-Sum of all side

A+B+C

10+8+6

answer :- 24

Answer 2

Solution!!

The length of the sides of the triangle are given and we have to calculate the area of the triangle.

Let the sides be a, b and c, respectively. So,

$\sf \bold{a = 10\:cm}$

$\sf \bold{b = 8\:cm}$

$\sf \bold{c = 6\:cm}$

We will calculate the area using $\sf \bold{Heron's\:Formula}$. Firstly, we have to calculate the semi perimeter.

$\sf \bold{semi\:perimeter\:(s) = \dfrac{a+b+c}{2}}$

s = $\sf \dfrac{10+8+6}{2}$

s = $\sf \dfrac{24}{2}$

$\sf \bold{s = 12\:cm}$

Now, let's calculate the area.

$\sf \bold{Area = \sqrt{s(s-a)(s-b)(s-c)}}$

Area = $\sf \sqrt{12(12-10)(12-8)(12-6)}$

Area = $\sf \sqrt{12\times 2\times 4\times 6}$

Area = $\sf \sqrt{576}$

$\sf \bold{Area = 24\:cm^{2}}$

Hence, the area of the triangle is 24 cm².