Question

what is the area of the triangle if 1 side is 12 and other two are 10​

Answer 1

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Sides of Triangle :-

A = 10cm

B = 10cm

C = 12cm

Semi perimeter = $\dfrac{Sum\:of\:all\:sides}{2}$

Semi perimeter = $\dfrac{A+B+C}{2}$

Substituting the value, we get

Semi perimeter = $\dfrac{10+10+12}{2}$

Semi perimeter = $\dfrac{32}{2}$

Semi perimeter = 16cm

Area = $\sqrt{S(s-a)(s-b)(s-c)}$

Area = $\sqrt{16(16-10)(16-10)(16-12)}$

Area = $\sqrt{16×6×6×4}$

Area = $\sqrt{2×2×2×2×2×3×2×3×2×2}$

Area = 2 × 2 × 2 × 2 × 3

Area = 48cm²

Answer 2

Answer:

48 cm^2

Step-by-step explanation:

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