Question

What is the area of the triangle whose sides measure 9 cm, 13 cm, and 20 cm?​

Answer 1

Given
= sides of triangle are 9cm, 13 cm, and 20 cm.

=Let, sides be
A=9cm
B=13cm
C=20cm

Semiperimeter (s) = (sum of all sides)/2
= (s) = (9+13+20)/2
= (s) = (42)/2
= (s) = 21cm

Area = √[s(s-a)(s-b)(s-c)]
= √[21(21-9)(21-13)(21-20)]
= √[21(12)(8)(1)]
= √[21(96)]
= √[2016]
= √[2*2*2*2*2*3*3*7]
= 2*2*3√[2*7]
=12√14 sq.cm

Hope it will help you.