Question

What is the area of the triangle whose vertices are 1,3 And 2,4 and 5,6?

Answer 1

Answer:

Step-by-step explanation:

(1,3) x¹ , y¹

(2,4) x² , y²

(5,6) x³ , y ³

Area = 1/2 [x¹(y²-y³) + x²(y³-y¹) + x³ ( y¹-y²)

= 1/2 [1(4-6) + 2(6-3) + 5(3-4)]

= 1/2[1(-2) + 2(3) + 5(-1)]

=1/2 [-2+6-5}

=1/2 × -1

= -1/2

Area can't be negative

So area = 0.5 sq unit

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