Question

what is the area of this figure​

Answer 1

area of ABT= 1/2*base*height

= 1/2*10*20

$= 100 {cm}^{2}$

area of UCB= 1/2*base*height

=1/2*10*20

$100 {cm}^{2}$

area of TDU

=1/2* base* height

=1/2*10*10

$50 {cm}^{2}$

area of ABCD= base *height

=20*20

$= 400 {cm}^{2}$

ar.(ABCD) =ar(ABT) +ar(BCU) +ar(TDU) +ar(BTU)

400=100+100+50+ar (BTU)

400=250+ar(BTU)

ar (BTU) = 150

$150 {cm}^{2}$

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