Question

What is the area of this figure?


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units²

Answer 1

Answer:

area of this figure is = area of 2 triangles +area of trapezium

Answer 2

The total area will be 54 sq. units.

Step-by-step explanation:

See the attached diagram.

The total area is divided into three regular zones. One trapezium ABCD, and two triangles Δ CEF and Δ DEG.

The area of the trapezium = $\frac{1}{2} \times ( AB + CD) \times (CB) = \frac{1}{2}(7 + 9)(6) = 48$ sq. units.

Now, the area of the two triangles = $\frac{1}{2}(CE) \times \textrm{Height} + \frac{1}{2}(DE)\times \textrm {Height}$

= $\frac{1}{2}(6)(1) + \frac{1}{2}(3)(2)$

= 3 + 3

= 6 sq. units.

Therefore, the total area will be (6 + 48) = 54 sq. units.