Question

what is the area of trapezium whose two parrellel sides are 10 cm and 12cm and height is 4cm​

Answer 1

Answer:

1/2×(sum of parallel sides)×height

Step-by-step explanation:

1/2×(10+12)×4

=2×22=44 cm^2

Answer 2

Answer:

$\large\bold\red{44\:{cm}^{2}}$

Step-by-step explanation:

Given,

A trapezium having parallel sides length as,

• L1 = 10 cm
• L2 = 12 cm

Also,

• Height, h = 4 cm

But,

We know that,

• Area,a = ½ × ( L1 + L2 ) × h

Therefore,

We get,

$= > a = \frac{1}{2} \times (10 + 12) \times 4 \\ \\ = > a = \frac{1}{2} \times 22 \times 4 \\ \\ = > a = 22 \times 2 \\ \\ = > a = 44 \: {cm}^{2}$

Hence,

Area of trapezium is $\bold{44\:{cm}^{2}}$