What is the area of trapezoid ABCD ?
Enter your answer as a decimal or whole number in the box. Do not round at any steps.
Answers
Hello !!
You can find the height.
dAB^2 = (xB - xA)^2 + (yB - yA)^2
dAB^2 = (1 - (-3))^2 + (5 - 2)^2
dAB^2 = (1 + 3)^2 + (3)^2
dAB^2 = (4)^2 + (3)^2
dAB^2 = 16 + 9
dAB^2 = 25
dAB = 25 uc
You can find the larger base.
dBC^2 = (xC - xB)^2 + (yC - yB)^2
dBC^2 = (7 - 1)^2 + (-3 - 5)^2
dBC^2 = (6)^2 + (-8)^2
dBC^2 = 36 + 64
dBC^2 = 100
dBC = 10 uc
Find the smaller base.
dAD^2 = (xD - xA)^2 + (yD - yA)^2
dAD^2 = (0 - (-3))^2 + (-2 - 2)^2
dAD^2 = (1 + 3)^2 + (-4)^2
dAD^2 = (4)^2 + (-4)^2
dAD^2 = 16 + 16
dAD^2 = 32
dAD = 4√2 uc
The area is give with this formula.
A = [(B + b) × h]/2
A = [(10 + 4√2) × 25]/2
A = [(10 + 5.656) × 25]/2
A = [15.656 × 25]/2
A = 391.4/2
A = 195.7 ua approximately
Final result : 195.7 ua approximately.
I hope I have collaborated and have a great day !
Answer:
37.5
Step-by-step explanation: Took the test, the other guy is wrong.