Question

what is the area of triangle

Answer 1

Given , hypotenuse(b)= 44 m

base (a) + height(c)= 88 m

by Pythagoras theorem ,

( b )^2 = a^2 + c^2

( b )^2 = a^2 + c^2 + 2ac - 2ac

b^2 = ( a + c )^2 - 2ac

2ac =( a + c )^2 - b^2

put, value of b = 44 m , a + c = 88 m

2ac = (88 )^2 - ( 44 ) ^2

2ac = 7744 - 1936

2ac = 5808

ac = 5808 / 2 = 2904

ac = 2904 m^2

a × c = 2904 m^2

base(a) × height(c) = 2904 m^2

since,we know that area of right angle triangle

=1 /2 × base × height

area of triangle=1 / 2 × 2904=1452m^2

therefore ,

required area of triangle = 1452 m^2

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Your Answer : Area = 1452 m^2
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