Question

what is the area of triangle ABC in which AB=BC=4 cm and angle B=90 degree

Answer 1

Answer:

according to the question the triangle is a isosceles right angle triangle.

so area of the triangle = (1/2) base×height.

base=height=4cm

=(1/2) ×4×4

=8cm^2

so area of the triangle will be 8cm^2.

Answer 2

A right triangle or right-angled triangle, or more formally an orthogonal triangle, formerly called a rectangled triangle.

Given:

$AB=BC=4cm.$ ∠$B=90$°

Find: The area of triangle

So, $AB=BC=4cm$

area of Δ$=\frac{1}{2}\times b\times h$

$=\frac{1}{2}\times 4\times4$

$=8cm^2.$