What is the area of triangle having sides 50 metres, 60metres, 60metres
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Step-by-step explanation:
it is a isosceles triangle...
if we draw a line segment with the middle it would be the height....
let ABC is the triangle &AD is the height...
AB =60,BC=50,AC=60
let triangle ABD
then,
by Pythagoras property,
AB^2=AD^2+BD^2
60^2=AD^2+25^2
3600=AD^2+625
3600-625=AD^2
2975=AD^2
do in this way......
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