Question

what is the area of triangle whose sides are 4 cm 3 cm and 5 cm?​

Answer 1

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The lengths of the sides are a = 4Cm, b = 3Cm, c = 5Cm.

∴ S = a + b + c / 2

= 4 + 3 + 5 / 2

= 6 Cm.

Use The Formula:-

Δ=√s(s−a)(s−b)(s−c)

= √ 6 ( 6 - 4 )( 6 - 3 )( 6 - 5 )

= √ 6 × 3 × 1 × 2 Sq.Cm

= 6 Sq.Cm

✿ 6 Sq.Cm ✿