what is the area of triangle whose sides are 5 cm 6 cm and root 61 CM
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Answered by
9
here is your answer dear frnd
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Answered by
3
according to the dimensions of the traingle, it is a right angled triangle as
![{5}^{2} + {6}^{2} = { \sqrt{61} }^{2} {5}^{2} + {6}^{2} = { \sqrt{61} }^{2}](https://tex.z-dn.net/?f=+%7B5%7D%5E%7B2%7D++%2B++%7B6%7D%5E%7B2%7D+++%3D+++%7B+%5Csqrt%7B61%7D+%7D%5E%7B2%7D+)
area is half into base into height which is
![0.5 \times 6 \times 5 = 15sq \: \: cm 0.5 \times 6 \times 5 = 15sq \: \: cm](https://tex.z-dn.net/?f=0.5+%5Ctimes+6+%5Ctimes+5+%3D+15sq+%5C%3A+%5C%3A+cm)
area is half into base into height which is
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