Question

What is the area of triangle whose vertices are (-40), (2,4) and (4,0)

Answer 1

$1 \div 2 \times (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)$
use this formula to calculate hope it helps mark as brainliest

Answer 2

A(-4,0) B(2,4) C(4,0), x1=-4,x2=2,x3=4, y1=0, y2 =4, y3= 0.
Area of the triangle = ½[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)]
= ½[-4(4) + 2(0) + 4(-4)]
= ½[-16 + 0 -16]
= ½× -32= -16
the area of the triangle are not negative. so, the vertices are not a triangle.

that helps you of brainlest