Math, asked by imsksingh2, 1 year ago

what is the area of triangle with side 3.5, 4.5 and 5.6

Answers

Answered by TooFree
0

Heron's Formula :

 \text {Area = }\sqrt{p(p-a)(p-b)(p-c)}  \text { where } p = \dfrac{a + b + c}{2}


Given that a = 3.5, b = 4.5 , c = 5.6


 p = \dfrac{3.5 + 4.5 + 5.6}{2}  = 6.8


 \text {Area = }\sqrt{6.8(6.8-3.5)(6.8-4.5)(6.8-5.6)} = 7.87 \text { units}^2 \text { (nearest hundredth)}


Answer: Area = 7.87 units²



imsksingh2: but i want any such short trick
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