Question

What is the area swept by minute hand in 5 minutes, if the length of the minute hand of a clock is 14cm? *
1 point
A.36.4 cm2
B.46.3 cm2
C.51.3 cm2
D.54.6 cm2​

Answer 1

Answer:

51.3 $cm^{2}$

Step-by-step explanation:

minute hand will cover 30 deg in its 5 minute move.

So Ф = 30 deg

Length of the hand will be radius of circle.

So r = 14 cm.

Now the area covered by hand = π$r^{2}$Ф / 360

  = 22/7 * 14 * 14 * 30 / 360

  = 51.3 $cm^{2}$