Question

what is the argument of -3i​

Answer 1

Explanation:

By definition the principal argument Arg(z) in usually defined in the interval (−π,π] therefore

Arg(8i)=π/2

If we do not refer to the principal value therefore we can use any

arg(8i)=π/2+2kπk∈Z

that is

8i=8ei(π/2+2kπ)