Question

What is the arithmetic series of the first twelve multiples of 6?

Answer 1

Answer:

We can arrange the multiples of 6 in increasing order, 0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96,… so that they form a simple pattern increasing by 6 at each step.

Answer 2

Given:

First twelve multiple of six

$6,12,18,24,30,36,42,48,54,60,66,72$

To find:

To find the arithmetic series of the first twelve multiples of six.

Step-by-step explanation:

• The arithmetic mean is a mathematical progression.
• It refers to the sequence of number series which difference remains to be the same and constant.

Solution:

$AP:\\\\a_{n} = a_{1} + (n+1 )d$

$a_{1} = 6\\d= 6\\n=12$

Now applying the formula

$a_{n} = 6 +(12 -1)6\\\\= 6+ 11*6\\\\=6+66\\\\=72\\\\a_{n} = 72$

Hence the arithmetic progression of twelve multiples of six is $72$