Question

what is the arithmetic squence when the first number is 10 and the sixth number is 40

Answer 1

Answer:

10,16,22,28,34,40

Step-by-step explanation:

a=10

n term = a+(n-1)d

6th term = 10+(6-1)d

40=10+5d

5d = 30

d=30/5

d=6

10+(1-1)6 , 10+(2-1)6, 10+(3-1)6 ,10+(4-1)6,10+(5-1)6

10,16, 22, 28, 34

Answer 2

To get the arithmetic sequence we should the value of a (ie., the first term in the sequence) and the value d (ie., the common difference between the terms in the sequence)

Thus, we are knowing the first term and now we have to find the value of d (common difference)

To get the common difference we have a formula

$a_{n} \: = \: a \: + \: (n - 1)d$

So, when we substitute the values to the above formula we get

$a_{6} \: = \: a \: + (6 \: - \: 1)d$

$40 \: = \: 10 \: + 5d$

$40 - 10 \: = 5d$

$30 \: = 5d$

$\frac{30}{5} = d$

$d = 6$

Therefore, the value of d is 6

Now we can form or construct the arithmetic sequence.

Hence the arithmetic sequence is

10, 16, 22, 28, 34, 40.

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