Question

What is the atomic number of the element located in group 16 period 2 of the periodic table?

Answer 1

$\bold{GIVEN,}$

• Group number = 16

So, the valency of the electron will be -2.

• Period number = 2

So, the number of shells in the atom will be 2

• When the number of shells are two the outermost shell should have to be stable by octate rule (can have eight electrons in the outermost shell)

So the outermost shell L can have not more than 8 electrons,since its valency is -2, so it means it needs two electrons ,

• Outermost shell will have = 8-2 = 6

But first shell should be statisfied by the 2 electrons .

• HENCE, its electronic configuration = (2,6)

Total number of electron will be = 2+6 = 8

We know ,

Atomic number is equal to total number of electron or total number of proton.

Z=e=p

So , its

$\bold{ATOMIC \: NUMBER=8}$

Oxygen lies in the group 16 and period 2 so the given element is Oxygen.