Chemistry, asked by tejaspatil01, 1 year ago

what is the atomic weight of an element x for which sample containing 1.58 into 10^22atoms weight 1.05 gram

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Answered by manjualikkal

no of moles = 1.58* 10^22 / 6.022* 10^ 23

=2.6 * 10^-2

atomic wt= 2.6 * 10^-2 * 1.05

= 2.73 * 10^-2 g

hope it help you ( if the answer has any sort of correction please inform)

tejaspatil01: but its ans. was 40

manjualikkal: No. of atoms in a sample = 1.58 × 10²² atoms.
Mass of the sample = 1.05 g.

Let the atomic mass of the element X be 'a' g/mole

Using the formula,
No. of moles = given Mass/Molar mass.
∴ No. of moles = 1.05/a

Now,
No. of atoms = No. of mole × Avogadro's number.
∴ 1.58 × 10²² = 1.05/a × 6.022 × 10²³
∴ a = 40.02 g

Thus, the atomic weight of the Element X is 40.02 g.

manjualikkal: sorry for the wrong answer

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what is the atomic weight of an element x for which sample containing 1.58 into 10^22atoms weight 1.05 gram​

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what is the atomic weight of an element x for which sample containing 1.58 into 10^22atoms weight 1.05 gram