What is the atomicity of the following compounds?
a) NaCl
b) Na2CO3
c) Al2O3
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1
Answer:
The number of atoms present in a molecule is called atomicity.
- Two
- Six
- Five
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Atomicity is the number of atoms in a molecule of an Element.
a) NaCl < Sodium Chloride > ( Na, Cl )
Number of Atoms in Na( Sodium ) = 1
Number of Atoms in Cl( Chlorine ) = 1
So, atomicity of NaCl is 1+1 = 2
b) Na2CO3 < Sodium Carbonate > ( Na, C, O )
Number of Atoms in Na( Sodium ) = 2
Number of Atoms in C( Carbon ) = 1
Number of Atoms in O( Oxygen ) = 3
So, atomicity of Na2CO3 is 2 + 1 + 3 = 6
c) Al2O3 < Aluminium Oxide > ( Al, O )
Number of Atoms in Al( Aluminium ) = 2
Number of Atoms in O( Oxygen ) = 3
So, atomicity of Al2O3 is 2 + 3 = 5
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