Question

what is the average acceleration if a cat moves 20 m/s to 50 m/s in 15 sec​

Answer 1

V = 50m/s

U = 20m/s

T = 15 s

We know ,

Acceleration = v-u/t

Now ,

a = (50-20)ms/15s

a = 30ms/15s

a = 2ms^-2

Answer 2

Answer:

2 m/s^2

Explanation:

Given,

Initial Velocity(u) = 20 m/s

Final Velocity(v) = 50 m/s

time(t) = 15s

To Find :-

Average Acceleration(a)

Formula Required :-

$a=\dfrac{v-u}{t}$

• a = acceleration
• v = final velocity
• u = initial velocity
• t = time

Solution :-

$a=\dfrac{50-20}{15}$

$=\dfrac{30}{15} m/s^2$

$= 2m/s^2$

∴ Average acceleration = a = 2 m/s^2

Know More :-

1. v = u + at

2. a = v - u/t

3. s = ut + 1/2 at^2

4. s = (u+v)t/2

5. v^2 - u^2 = 2as

• v = final velocity
• u = initial velocity
• a = acceleration
• t = time

• s = distance